Optimal. Leaf size=157 \[ \frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}+\frac {2 b c \sqrt {d} x \text {ArcTan}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {-1+c^2 x^2}}\right )}{e^2 \sqrt {c^2 x^2}}-\frac {b x \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {-1+c^2 x^2}}{c \sqrt {d+e x^2}}\right )}{e^{3/2} \sqrt {c^2 x^2}} \]
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Rubi [A]
time = 0.19, antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 11, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.478, Rules used = {272, 45, 5346,
12, 587, 163, 65, 223, 212, 95, 210} \begin {gather*} \frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}+\frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {2 b c \sqrt {d} x \text {ArcTan}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {c^2 x^2-1}}\right )}{e^2 \sqrt {c^2 x^2}}-\frac {b x \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {c^2 x^2-1}}{c \sqrt {d+e x^2}}\right )}{e^{3/2} \sqrt {c^2 x^2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 45
Rule 65
Rule 95
Rule 163
Rule 210
Rule 212
Rule 223
Rule 272
Rule 587
Rule 5346
Rubi steps
\begin {align*} \int \frac {x^3 \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^{3/2}} \, dx &=\frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}-\frac {(b c x) \int \frac {2 d+e x^2}{e^2 x \sqrt {-1+c^2 x^2} \sqrt {d+e x^2}} \, dx}{\sqrt {c^2 x^2}}\\ &=\frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}-\frac {(b c x) \int \frac {2 d+e x^2}{x \sqrt {-1+c^2 x^2} \sqrt {d+e x^2}} \, dx}{e^2 \sqrt {c^2 x^2}}\\ &=\frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}-\frac {(b c x) \text {Subst}\left (\int \frac {2 d+e x}{x \sqrt {-1+c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{2 e^2 \sqrt {c^2 x^2}}\\ &=\frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}-\frac {(b c d x) \text {Subst}\left (\int \frac {1}{x \sqrt {-1+c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{e^2 \sqrt {c^2 x^2}}-\frac {(b c x) \text {Subst}\left (\int \frac {1}{\sqrt {-1+c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{2 e \sqrt {c^2 x^2}}\\ &=\frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}-\frac {(2 b c d x) \text {Subst}\left (\int \frac {1}{-d-x^2} \, dx,x,\frac {\sqrt {d+e x^2}}{\sqrt {-1+c^2 x^2}}\right )}{e^2 \sqrt {c^2 x^2}}-\frac {(b x) \text {Subst}\left (\int \frac {1}{\sqrt {d+\frac {e}{c^2}+\frac {e x^2}{c^2}}} \, dx,x,\sqrt {-1+c^2 x^2}\right )}{c e \sqrt {c^2 x^2}}\\ &=\frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}+\frac {2 b c \sqrt {d} x \tan ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {-1+c^2 x^2}}\right )}{e^2 \sqrt {c^2 x^2}}-\frac {(b x) \text {Subst}\left (\int \frac {1}{1-\frac {e x^2}{c^2}} \, dx,x,\frac {\sqrt {-1+c^2 x^2}}{\sqrt {d+e x^2}}\right )}{c e \sqrt {c^2 x^2}}\\ &=\frac {d \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \sec ^{-1}(c x)\right )}{e^2}+\frac {2 b c \sqrt {d} x \tan ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {-1+c^2 x^2}}\right )}{e^2 \sqrt {c^2 x^2}}-\frac {b x \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {-1+c^2 x^2}}{c \sqrt {d+e x^2}}\right )}{e^{3/2} \sqrt {c^2 x^2}}\\ \end {align*}
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Mathematica [A]
time = 0.96, size = 147, normalized size = 0.94 \begin {gather*} \frac {\left (2 d+e x^2\right ) \left (a+b \sec ^{-1}(c x)\right )}{e^2 \sqrt {d+e x^2}}-\frac {b \sqrt {1-\frac {1}{c^2 x^2}} x \left (2 c \sqrt {d} \text {ArcTan}\left (\frac {\sqrt {d} \sqrt {-1+c^2 x^2}}{\sqrt {d+e x^2}}\right )+\sqrt {e} \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {-1+c^2 x^2}}{c \sqrt {d+e x^2}}\right )\right )}{e^2 \sqrt {-1+c^2 x^2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 2.44, size = 0, normalized size = 0.00 \[\int \frac {x^{3} \left (a +b \,\mathrm {arcsec}\left (c x \right )\right )}{\left (e \,x^{2}+d \right )^{\frac {3}{2}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 273 vs.
\(2 (132) = 264\).
time = 3.96, size = 572, normalized size = 3.64 \begin {gather*} \left [\frac {{\left (b x^{2} e + b d\right )} e^{\frac {1}{2}} \log \left (c^{4} d^{2} - 4 \, {\left (c^{3} d + {\left (2 \, c^{3} x^{2} - c\right )} e\right )} \sqrt {c^{2} x^{2} - 1} \sqrt {x^{2} e + d} e^{\frac {1}{2}} + {\left (8 \, c^{4} x^{4} - 8 \, c^{2} x^{2} + 1\right )} e^{2} + 2 \, {\left (4 \, c^{4} d x^{2} - 3 \, c^{2} d\right )} e\right ) + 2 \, {\left (b c x^{2} e + b c d\right )} \sqrt {-d} \log \left (\frac {c^{4} d^{2} x^{4} - 8 \, c^{2} d^{2} x^{2} + x^{4} e^{2} - 4 \, {\left (c^{2} d x^{2} - x^{2} e - 2 \, d\right )} \sqrt {c^{2} x^{2} - 1} \sqrt {x^{2} e + d} \sqrt {-d} + 8 \, d^{2} - 2 \, {\left (3 \, c^{2} d x^{4} - 4 \, d x^{2}\right )} e}{x^{4}}\right ) + 4 \, {\left (a c x^{2} e + 2 \, a c d + {\left (b c x^{2} e + 2 \, b c d\right )} \operatorname {arcsec}\left (c x\right )\right )} \sqrt {x^{2} e + d}}{4 \, {\left (c x^{2} e^{3} + c d e^{2}\right )}}, \frac {{\left (b x^{2} e + b d\right )} e^{\frac {1}{2}} \log \left (c^{4} d^{2} - 4 \, {\left (c^{3} d + {\left (2 \, c^{3} x^{2} - c\right )} e\right )} \sqrt {c^{2} x^{2} - 1} \sqrt {x^{2} e + d} e^{\frac {1}{2}} + {\left (8 \, c^{4} x^{4} - 8 \, c^{2} x^{2} + 1\right )} e^{2} + 2 \, {\left (4 \, c^{4} d x^{2} - 3 \, c^{2} d\right )} e\right ) + 4 \, {\left (b c x^{2} e + b c d\right )} \sqrt {d} \arctan \left (-\frac {{\left (c^{2} d x^{2} - x^{2} e - 2 \, d\right )} \sqrt {c^{2} x^{2} - 1} \sqrt {x^{2} e + d} \sqrt {d}}{2 \, {\left (c^{2} d^{2} x^{2} - d^{2} + {\left (c^{2} d x^{4} - d x^{2}\right )} e\right )}}\right ) + 4 \, {\left (a c x^{2} e + 2 \, a c d + {\left (b c x^{2} e + 2 \, b c d\right )} \operatorname {arcsec}\left (c x\right )\right )} \sqrt {x^{2} e + d}}{4 \, {\left (c x^{2} e^{3} + c d e^{2}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{3} \left (a + b \operatorname {asec}{\left (c x \right )}\right )}{\left (d + e x^{2}\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^3\,\left (a+b\,\mathrm {acos}\left (\frac {1}{c\,x}\right )\right )}{{\left (e\,x^2+d\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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